Greg Egan on Nostr: For x>0, define L(x)=log(x)/x. L'(x) = (1-log(x))/x^2 has its sole zero at x=e. So ...
For x>0, define L(x)=log(x)/x.
L'(x) = (1-log(x))/x^2 has its sole zero at x=e.
So L(x) ≤ 1/e, with equality only at x=e.
This means:
e log(x) ≤ x
x^e ≤ e^x
for all x>0, with equality only at x=e.
Published at
2026-02-08 23:41:04 UTCEvent JSON
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