- I don't know which SU(2) x SU(2) subgroup of GSM you're talking about, since GSM = (SU(3) x SU(2) x U(1))/(Z_6). This has a continuum of SU(2) x SU(2) subgroups. It's possible they are all conjugate, but don't quote me on that!
"What should one do exactly, if one has a theory of physics, but is not connected to academia?"
I get about 2 papers from people in this situation each day in my email, and I respond politely that I don't have the time to read them.
To get taken seriously, you really need to publlish your paper in a decent journal. Most of the people who send me their papers will never manage to do that (and for good reasons).
